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The sample injection volume was 20 L

Step 1 Mean of tar levels (x) = (24 + 14 + 0.5 + 0.8 + 0.8 + 1.5 + 1.2) / 7 = 42.8 / 7 = 6.114 Mean of nicotine levels () = (0.5 + 0.8 + 0.8 + 1.5 + 1.2) / 7 = 4.8 / 7 = 0.686 Show more Show all steps Avi Zellman and 63 other Intro Stats / AP Statistics educators are ready to help you

It can reduce or cancel out the benefit of lower toxin readings seen in lab tests

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